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[R] Extract rows from a list object

Vladimir Mikryukov

2010-08-24

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Dear list members,

I need to create a table from a huge list object,
this list consists of matrices of the same size (but with different
content).

The resulting n tables should contain the same rows from all matrices.

For example:
n <- 23
x <- array(1:20, dim=c(n,6))

huge.list <- list()
for (i in 1:1000) {
  huge.list[[i]] <- x }


# One of 1000 matrices
huge.list[[1]][1:4, 1:6]
  [,1] [,2] [,3] [,4] [,5] [,6]
[1,]   1   4   7  10  13  16
[2,]   2   5   8  11  14  17
[3,]   3   6   9  12  15  18
[4,]   4   7  10  13  16  19
...

# The result should be like that:
# One of n tables (with the row 4 from all 1000 matrices):
  [,1] [,2] [,3] [,4] [,5] [,6]
[1,]   4   7  10  13  16  19
[2,]   4   7  10  13  16  19
[3,]   4   7  10  13  16  19
[4,]   4   7  10  13  16  19
...
[999,]   4   7  10  13  16  19
[1000,]   4   7  10  13  16  19


# I tried to convert a list object to an array
ARR <- array(unlist(huge.list), dim = c(dim(huge.list[[1]]),
length(huge.list)))
# then split it and use abind function, but it didn't work

Thanks in advance!
Vladimir

--
Vladimir Mikryukov
PhD student
Institute of Plant & Animal Ecology UD RAS,
Lab. of Population and Community Ecotoxicology
[8 Marta 202, 620144, Ekaterinburg, Russia]
Tel. +7 343 210 38 58 (ext.290)
Fax: +7 343 260 82 56, +7 343 260 65 00

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